Add generic simple dijkstra method.
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@ -1,81 +1,58 @@
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import heapq
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from typing import Any, Iterator, TypeAlias, cast
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from typing import Any, Iterator
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from ..base import BaseSolver
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Node: TypeAlias = tuple[int, int]
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def dijkstra(
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grid: list[Node],
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n_rows: int,
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n_cols: int,
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start: Node = (0, 0),
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target: Node | None = None,
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) -> tuple[Node, ...] | None:
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corrupted = set(grid)
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target = target or (n_rows - 1, n_cols - 1)
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queue: list[tuple[int, Node, tuple[Node, ...]]] = [(0, start, (start,))]
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preds: dict[Node, tuple[Node, ...]] = {}
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while queue:
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dis, node, path = heapq.heappop(queue)
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if node in preds:
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continue
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preds[node] = path
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if node == target:
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break
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row, col = node
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for dr, dc in ((-1, 0), (0, 1), (1, 0), (0, -1)):
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row_n, col_n = row + dr, col + dc
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if (
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0 <= row_n < n_rows
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and 0 <= col_n < n_cols
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and (row_n, col_n) not in corrupted
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and (row_n, col_n) not in preds
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):
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heapq.heappush(
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queue, (dis + 1, (row_n, col_n), path + ((row_n, col_n),))
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)
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return preds.get(target, None)
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from ..tools import graphs
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class Solver(BaseSolver):
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def print_grid(self, grid: list[tuple[int, int]], n_rows: int, n_cols: int):
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values = set(grid)
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for row in range(n_rows):
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self.logger.info(
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"".join("#" if (row, col) in values else "." for col in range(n_cols))
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if self.files:
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self.files.create(
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"graph.txt",
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"\n".join(
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"".join(
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"#" if (row, col) in values else "." for col in range(n_cols)
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)
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for row in range(n_rows)
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).encode(),
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text=True,
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)
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else:
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for row in range(n_rows):
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self.logger.info(
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"".join(
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"#" if (row, col) in values else "." for col in range(n_cols)
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)
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)
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def dijkstra(self, corrupted: list[tuple[int, int]], n_rows: int, n_cols: int):
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return graphs.dijkstra(
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(0, 0),
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(n_rows - 1, n_cols - 1),
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graphs.make_neighbors_grid_fn(n_rows, n_cols, set(corrupted)),
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)
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def solve(self, input: str) -> Iterator[Any]:
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values = [
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cast(tuple[int, int], tuple(map(int, row.split(","))))
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for row in input.splitlines()
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(int(p[0]), int(p[1])) for r in input.splitlines() if (p := r.split(","))
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]
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n_rows, n_cols = (7, 7) if len(values) < 100 else (71, 71)
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_is_test = len(values) < 100
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n_rows, n_cols, n_bytes_p1 = (7, 7, 12) if _is_test else (71, 71, 1024)
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n_bytes_p1 = 12 if len(values) < 100 else 1024
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bytes_p1 = values[:n_bytes_p1]
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self.print_grid(bytes_p1, n_rows, n_cols)
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path_p1 = dijkstra(bytes_p1, n_rows, n_cols)
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assert path_p1 is not None
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yield len(path_p1) - 1
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path_p1, cost_p1 = self.dijkstra(bytes_p1, n_rows, n_cols) or ((), -1)
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yield cost_p1
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path = path_p1
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for b in range(n_bytes_p1, len(values)):
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if values[b] not in path:
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continue
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path = dijkstra(values[: b + 1], n_rows, n_cols)
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path, _ = self.dijkstra(values[: b + 1], n_rows, n_cols) or (None, -1)
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if path is None:
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yield ",".join(map(str, values[b]))
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break
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95
src/holt59/aoc/tools/graphs.py
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95
src/holt59/aoc/tools/graphs.py
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@ -0,0 +1,95 @@
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import heapq
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from typing import Callable, Iterable, TypeVar
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_Node = TypeVar("_Node")
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def make_neighbors_grid_fn(
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rows: int | Iterable[int],
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cols: int | Iterable[int],
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excluded: Iterable[tuple[int, int]] = set(),
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diagonals: bool = False,
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):
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"""
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Create a neighbors function suitable for graph function for a simple grid.
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Args:
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rows: Rows of the grid. If an int is specified, the rows are assumed to be
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numbered from 0 to rows - 1, otherwise the iterable should contain the list
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of valid rows.
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cols: Columns of the grid. If an int is specified, the columns are assumed to be
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numbered from 0 to cols - 1, otherwise the iterable should contain the list
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of valid columns.
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excluded: Cells of the grid that cannot be used as valid nodes for the graph.
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diagonals: If True, neighbors will include diagonal cells, otherwise, only
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horizontal and vertical neighbors will be included.
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"""
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ds = ((-1, 0), (0, 1), (1, 0), (0, -1))
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if diagonals:
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ds = ds + ((-1, -1), (-1, 1), (1, -1), (1, 1))
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if isinstance(rows, int):
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rows = range(rows)
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elif not isinstance(rows, range):
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rows = set(rows)
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if isinstance(cols, int):
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cols = range(cols)
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elif not isinstance(cols, range):
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cols = set(cols)
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excluded = set(excluded)
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def _fn(node: tuple[int, int]):
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return (
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((row_n, col_n), 1)
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for dr, dc in ds
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if (row_n := node[0] + dr) in rows
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and (col_n := node[1] + dc) in cols
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and (row_n, col_n) not in excluded
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)
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return _fn
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def dijkstra(
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start: _Node,
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target: _Node,
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neighbors: Callable[[_Node], Iterable[tuple[_Node, float]]],
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) -> tuple[tuple[_Node, ...], float] | None:
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"""
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Solve shortest-path problem using simple Dijkstra algorithm from start to target,
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using the given neighbors function.
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Args:
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start: Starting node of the path.
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target: Target node for the path.
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neighbors: Function that should return, for a given node, the list of
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its neighbors with the cost to go from the node to the neighbor.
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Returns:
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One of the shortest-path from start to target with its associated cost, if one
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is found, otherwise None.
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"""
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queue: list[tuple[float, _Node, tuple[_Node, ...]]] = [(0, start, (start,))]
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preds: dict[_Node, tuple[tuple[_Node, ...], float]] = {}
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while queue:
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dis, node, path = heapq.heappop(queue)
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if node in preds:
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continue
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preds[node] = (path, dis)
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if node == target:
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break
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for neighbor, cost in neighbors(node):
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if neighbor in preds:
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continue
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heapq.heappush(queue, (dis + cost, neighbor, path + (neighbor,)))
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return preds.get(target, None)
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