Day 21.
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106
2022/day21.py
106
2022/day21.py
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# -*- encoding: utf-8 -*-
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# -*- encoding: utf-8 -*-
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import operator
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import sys
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import sys
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from typing import Callable
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def compute(monkeys: dict[str, int | tuple[str, str, str]], monkey: str) -> int:
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value = monkeys[monkey]
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if isinstance(value, int):
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return value
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else:
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op: dict[str, Callable[[int, int], int]] = {
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"+": operator.add,
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"-": operator.sub,
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"*": operator.mul,
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"/": operator.floordiv,
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}
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value = op[value[1]](compute(monkeys, value[0]), compute(monkeys, value[2]))
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monkeys[monkey] = value
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return value
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def invert(
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monkeys: dict[str, int | tuple[str, str, str]], monkey: str, target: int
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) -> dict[str, int | tuple[str, str, str]]:
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"""
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Revert the given mapping from monkey name to value or operation such that
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the value from 'monkey' is computable by inverting operation until the root is
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found.
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Args:
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monkeys: Dictionary of monkeys, that will be updated and returned.
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monkey: Name of the monkey to start from.
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target: Target value to set for the monkey that depends on root.
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Returns:
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The given dictionary of monkeys.
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"""
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monkeys = monkeys.copy()
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depends: dict[str, str] = {}
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for m, v in monkeys.items():
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if isinstance(v, int):
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continue
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op1, _, op2 = v
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assert op1 not in depends
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assert op2 not in depends
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depends[op1] = m
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depends[op2] = m
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invert_op = {"+": "-", "-": "+", "*": "/", "/": "*"}
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current = monkey
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while True:
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dep = depends[current]
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if dep == "root":
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monkeys[current] = target
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break
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val = monkeys[dep]
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assert not isinstance(val, int)
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op1, ope, op2 = val
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if op1 == current:
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monkeys[current] = (dep, invert_op[ope], op2)
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elif ope in ("+", "*"):
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monkeys[current] = (dep, invert_op[ope], op1)
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else:
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monkeys[current] = (op1, ope, dep)
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current = dep
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return monkeys
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lines = sys.stdin.read().splitlines()
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monkeys: dict[str, int | tuple[str, str, str]] = {}
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op_monkeys: set[str] = set()
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for line in lines:
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parts = line.split(":")
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name = parts[0].strip()
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try:
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value = int(parts[1].strip())
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monkeys[name] = value
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except ValueError:
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op1, ope, op2 = parts[1].strip().split()
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monkeys[name] = (op1, ope, op2)
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op_monkeys.add(name)
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answer_1 = compute(monkeys.copy(), "root")
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print(f"answer 1 is {answer_1}")
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# assume the second operand of 'root' can be computed, and the first one depends on
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# humn, which is the case is my input and the test input
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p1, _, p2 = monkeys["root"] # type: ignore
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answer_2 = compute(invert(monkeys, "humn", compute(monkeys.copy(), p2)), "humn")
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print(f"answer 2 is {answer_2}")
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File diff suppressed because it is too large
Load Diff
@ -0,0 +1,15 @@
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root: pppw + sjmn
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dbpl: 5
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cczh: sllz + lgvd
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zczc: 2
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ptdq: humn - dvpt
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dvpt: 3
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lfqf: 4
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humn: 5
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ljgn: 2
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sjmn: drzm * dbpl
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sllz: 4
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pppw: cczh / lfqf
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lgvd: ljgn * ptdq
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drzm: hmdt - zczc
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hmdt: 32
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