Refactor code for API (#3)

Co-authored-by: Mikael CAPELLE <mikael.capelle@thalesaleniaspace.com>
Co-authored-by: Mikaël Capelle <capelle.mikael@gmail.com>
Reviewed-on: #3
This commit is contained in:
2024-12-08 13:06:41 +00:00
parent ab4e3e199c
commit ce315b8778
130 changed files with 4599 additions and 3336 deletions

View File

@@ -1,56 +1,58 @@
import sys
from collections import defaultdict
from typing import Any, Iterator
replacements_s, molecule = sys.stdin.read().split("\n\n")
REPLACEMENTS: dict[str, list[str]] = defaultdict(list)
for replacement_s in replacements_s.splitlines():
p = replacement_s.split(" => ")
REPLACEMENTS[p[0]].append(p[1])
molecule = molecule.strip()
generated = [
molecule[:i] + replacement + molecule[i + len(symbol) :]
for symbol, replacements in REPLACEMENTS.items()
for replacement in replacements
for i in range(len(molecule))
if molecule[i:].startswith(symbol)
]
answer_1 = len(set(generated))
print(f"answer 1 is {answer_1}")
inversion: dict[str, str] = {
replacement: symbol
for symbol, replacements in REPLACEMENTS.items()
for replacement in replacements
}
# there is actually only one way to create the molecule, and we can greedily replace
# tokens with their replacements, e.g., if H => OH then we can replace OH by H directly
# without thinking
count = 0
while molecule != "e":
i = 0
m2 = ""
while i < len(molecule):
found = False
for replacement in inversion:
if molecule[i:].startswith(replacement):
m2 += inversion[replacement]
i += len(replacement)
count += 1
found = True
break
if not found:
m2 += molecule[i]
i += 1
# print(m2)
molecule = m2
from ..base import BaseSolver
answer_2 = count
print(f"answer 2 is {count}")
class Solver(BaseSolver):
def solve(self, input: str) -> Iterator[Any]:
replacements_s, molecule = input.split("\n\n")
REPLACEMENTS: dict[str, list[str]] = defaultdict(list)
for replacement_s in replacements_s.splitlines():
p = replacement_s.split(" => ")
REPLACEMENTS[p[0]].append(p[1])
molecule = molecule.strip()
generated = [
molecule[:i] + replacement + molecule[i + len(symbol) :]
for symbol, replacements in REPLACEMENTS.items()
for replacement in replacements
for i in range(len(molecule))
if molecule[i:].startswith(symbol)
]
yield len(set(generated))
inversion: dict[str, str] = {
replacement: symbol
for symbol, replacements in REPLACEMENTS.items()
for replacement in replacements
}
# there is actually only one way to create the molecule, and we can greedily replace
# tokens with their replacements, e.g., if H => OH then we can replace OH by H directly
# without thinking
count = 0
while molecule != "e":
i = 0
m2 = ""
while i < len(molecule):
found = False
for replacement in inversion:
if molecule[i:].startswith(replacement):
m2 += inversion[replacement]
i += len(replacement)
count += 1
found = True
break
if not found:
m2 += molecule[i]
i += 1
# print(m2)
molecule = m2
yield count