Add generic simple dijkstra method.
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This commit is contained in:
Mikael CAPELLE
2024-12-18 09:01:31 +01:00
parent 954ef1e6ce
commit 146d025d41
2 changed files with 128 additions and 56 deletions

View File

@@ -0,0 +1,95 @@
import heapq
from typing import Callable, Iterable, TypeVar
_Node = TypeVar("_Node")
def make_neighbors_grid_fn(
rows: int | Iterable[int],
cols: int | Iterable[int],
excluded: Iterable[tuple[int, int]] = set(),
diagonals: bool = False,
):
"""
Create a neighbors function suitable for graph function for a simple grid.
Args:
rows: Rows of the grid. If an int is specified, the rows are assumed to be
numbered from 0 to rows - 1, otherwise the iterable should contain the list
of valid rows.
cols: Columns of the grid. If an int is specified, the columns are assumed to be
numbered from 0 to cols - 1, otherwise the iterable should contain the list
of valid columns.
excluded: Cells of the grid that cannot be used as valid nodes for the graph.
diagonals: If True, neighbors will include diagonal cells, otherwise, only
horizontal and vertical neighbors will be included.
"""
ds = ((-1, 0), (0, 1), (1, 0), (0, -1))
if diagonals:
ds = ds + ((-1, -1), (-1, 1), (1, -1), (1, 1))
if isinstance(rows, int):
rows = range(rows)
elif not isinstance(rows, range):
rows = set(rows)
if isinstance(cols, int):
cols = range(cols)
elif not isinstance(cols, range):
cols = set(cols)
excluded = set(excluded)
def _fn(node: tuple[int, int]):
return (
((row_n, col_n), 1)
for dr, dc in ds
if (row_n := node[0] + dr) in rows
and (col_n := node[1] + dc) in cols
and (row_n, col_n) not in excluded
)
return _fn
def dijkstra(
start: _Node,
target: _Node,
neighbors: Callable[[_Node], Iterable[tuple[_Node, float]]],
) -> tuple[tuple[_Node, ...], float] | None:
"""
Solve shortest-path problem using simple Dijkstra algorithm from start to target,
using the given neighbors function.
Args:
start: Starting node of the path.
target: Target node for the path.
neighbors: Function that should return, for a given node, the list of
its neighbors with the cost to go from the node to the neighbor.
Returns:
One of the shortest-path from start to target with its associated cost, if one
is found, otherwise None.
"""
queue: list[tuple[float, _Node, tuple[_Node, ...]]] = [(0, start, (start,))]
preds: dict[_Node, tuple[tuple[_Node, ...], float]] = {}
while queue:
dis, node, path = heapq.heappop(queue)
if node in preds:
continue
preds[node] = (path, dis)
if node == target:
break
for neighbor, cost in neighbors(node):
if neighbor in preds:
continue
heapq.heappush(queue, (dis + cost, neighbor, path + (neighbor,)))
return preds.get(target, None)